14x^2=-63x

Solution for 14x^2=-63x equation:

14x^2=-63x

We move all terms to the left:

14x^2-(-63x)=0

We get rid of parentheses

14x^2+63x=0

a = 14; b = 63; c = 0;
Δ = b2-4ac
Δ = 632-4·14·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-63}{2*14}=\frac{-126}{28}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+63}{2*14}=\frac{0}{28}
=0
$